Question

I have User class which has a field type, which is in turn a list.

So type might look like : ["a","b"]

I have a another list, say search like ["c","b"] (this is pre-defined)

Now what I want is to search all my User instances such that I can find users type matching with any one of the elements from search.

I came up with a partial solution :

def newQ = User.findAllByUsernameIsNotNull()
newQ.each { eachIndex ->
                    query = eachIndex.type
                    result = query.findAll { it == "c" }
                    if(result.size() > 0 )
                    {
                        ans << eachIndex.username
                    }
                  }

The above code works, ans list have all User which satisfy my condition. But you can clearly see that in query.findAll line, I’m doing a search only for one element from search. I want to perform search operation for all search element against query(which is User‘s type field).

How can I achieve that? Apart from my solution are there any easy way to do that?

Thanks in advance.

Answer 1

You could do something like:

def ans = []
search.each{s->
    ans += User.findAll("from User u where u.username is not null and ? in elements(u.type)",[s])
}

I can’t think of a way to do it in a single query