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I have values like this:
long millis = 11400000;
int consta = 86400000;
double res = millis/consta;
The question is: why res equals 0.0 (instead of ca. 0.131944)? It’s stored in double so there should be no rounding right?
When you are using a binary operator, both arguments should be of a same type and the result will be in their type too. When you want to divide
(int)/(long)it turns into(long)/(long)and the result is(long). you shouldmake it(double)/(long)or(int)/(double)to get a double result. Since double is greater that int and long, int and long will be turned into double in(double)/(long)and(int)/(double)