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Home/ Questions/Q 581947
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T14:38:03+00:00 2026-05-13T14:38:03+00:00

I have various classes that implements IActiveRecord. I want to have a method where

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I have various classes that implements IActiveRecord.

I want to have a method where I pass in a newly created class and assign ActiveRecord to the type of the class passed in.

I have tried the below but it does not compile for some reason.

Any ideas?

private void AddRecord<T>() where T : class, new()
        {

            IActiveRecord ActiveRecord = (IActiveRecord)T;
        }
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  1. Editorial Team
    Editorial Team
    2026-05-13T14:38:03+00:00Added an answer on May 13, 2026 at 2:38 pm

    Your question is unclear, but if I understand correctly what you are trying to do, you just need to add the constraint where T : IActiveRecord. Then you can say

    void AddRecord<T>() where T : IActiveRecord, new() { 
        IActiveRecord activeRecord = new T();
        // more stuff
    }
    

    Regarding your line

    IActiveRecord ActiveRecord = (IActiveRecord)T;

    this is not legal. T is a type parameter, not an expression that you can cast.

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