I have working C++ code using swig which creates a struct, passes it to lua (essentially by reference), and allows manipulation of the struct such that the changes made in the lua code remain once I’ve returned to the C++ function. This all works fine until I add a std::string to the struct, as shown here:
struct stuff
{
int x;
int y;
std::string z;
};
I’m unable to modify the std::string because it’s apparently passed as a const reference. If I attempt to assign a value to this string in my lua function I get this error:
Error in str (arg 2), expected ‘std::string const &’ got ‘string’
What is the proper way to address this problem? Do I have to write some custom C++ function to set z rather than using normal syntax like obj.z = "hi"? Is there some way to allow this assignment using swig?
The C++ code is
#include <stdio.h>
#include <string.h>
extern "C" {
#include "lua.h"
#include "lualib.h"
#include "lauxlib.h"
}
#include "example_wrap.hxx"
extern int luaopen_example(lua_State* L); // declare the wrapped module
int main()
{
char buff[256];
const char *cmdstr = "print(33)\n";
int error;
lua_State *L = lua_open();
luaL_openlibs(L);
luaopen_example(L);
struct stuff b;
b.x = 1;
b.y = 2;
SWIG_NewPointerObj(L, &b, SWIGTYPE_p_stuff, 0);
lua_setglobal(L, "b");
while (fgets(buff, sizeof(buff), stdin) != NULL) {
error = luaL_loadbuffer(L, buff, strlen(buff), "line") ||
lua_pcall(L, 0, 0, 0);
if (error) {
fprintf(stderr, "%s", lua_tostring(L, -1));
lua_pop(L, 1); /* pop error message from the stack */
}
}
printf("B.y now %d\n", b.y);
printf("Str now %s\n", b.str.c_str());
luaL_dostring(L, cmdstr);
lua_close(L);
return 0;
}
You need to add
%include <std_string.i>to your SWIG module. Otherwise, it does not know how to map a Luastringto an C++std::string.