Question

I have written a case as shown below,

case 'yesno':
{
    if ($reg['answer'])
    {
        $reg['answer'] = $phrase['_yes'];

    }
    else
    {
        $reg['answer'] = $phrase['_no'];
    }
//below line is to be corrected 
($reg['answer'] =$phrase['_yes'])? $show['answer_icon'] = true : $show['answer_icon'] = false;
        echo $show['answer_icon'];
    break;
 }

I need to show an image as result only if

     $reg['answer'] = $phrase['_yes']; 

But right now the condition which I have written for that is showing error(above comemnted line)

It shows all result with an image,irrestpective of yes or no when I write the below condition

    ($reg['answer'])? $show['answer_icon'] = true : $show['answer_icon'] = false;

Can any one suggest the right condition for this… Showing an image part has been done.

Answer 1

Close buddy. Try this:

 $show['answer_icon'] = ($reg['answer'] == $phrase['_yes']) ? true : false;