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Home/ Questions/Q 6918639
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T09:53:07+00:00 2026-05-27T09:53:07+00:00

I have written a code in C which works fine for int but when

  • 0

I have written a code in C which works fine for int but when I try to do this with float it is showing error what can i do to make it correct.

#include<stdio.h>

int main()
{
    float a,y;
    float square();
    scanf("%f", &a);
    y = square( a );
    printf("%f %f ",a ,y);
}

float square(float b)
{
    float z;
    z = b*b;
    printf("%f %f",z ,b);
    return(z);
}

error:

return.c:12: error: conflicting types for 'square'
return.c:13: note: an argument type that has a default promotion can't match an empty parameter name list declaration
return.c:6: note: previous declaration of 'square' was here
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T09:53:08+00:00Added an answer on May 27, 2026 at 9:53 am

    Move the declaration of square() out of the function and make sure the prototype matches:

    float square(float b);  //  Make sure this matches the definition.
    
    int main()
    {
        float a,y;
        scanf("%f", &a);
        y = square( a );
        printf("%f %f ",a ,y);
    }
    
    float square(float b)
    {
        float z;
        z = b*b;
        printf("%f %f",z ,b);
        return(z);
    }
    

    As for why it “worked” for int, you’ll have to show us the exact code you used for that case.

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