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Home/ Questions/Q 1055247
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T17:32:00+00:00 2026-05-16T17:32:00+00:00

I have written a code that maps to a shared memory location,so that the

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I have written a code that maps to a shared memory location,so that the first program opens a shared memory block and stores some data in it.And the second program reads the shared data.

Whats the difference between the two command lines:

1.

 if(argc<2)
 {
     printf("USAGE:%s text-to-share\n",argv[0]);
 }

This code gives me a Segmentation Fault if I run it without the second argument.
However it works fine when I enter in some data.

2.

 if(argc<2)
    return printf("USAGE:%s text-to-share\n",argv[0]);

This one serves my purpose.

But I fail to understand the difference between the two.
I’m a novice.For me the two are same,because ideally they should have the same output.
Please Help!

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  1. Editorial Team
    Editorial Team
    2026-05-16T17:32:00+00:00Added an answer on May 16, 2026 at 5:32 pm

    why first statment giving you segmentation fault,in C it name of the program which you are executing,so it should be absolutely fine.I am able to execute this testcase properly

    int main(int argc,char ** argv){
        if(argc<2)
         {
             printf("USAGE:%s text-to-share\n",argv[0]);
         }
        return 0;
     }
    

    it output :

    USAGE:./prog text-to-share
    

    except you are doing something wrong in the code executed before this.

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