Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 871025
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 15, 20262026-05-15T10:34:33+00:00 2026-05-15T10:34:33+00:00

I have written a jquery-ui widget using the Widget Factory… I need to be

  • 0

I have written a jquery-ui widget using the Widget Factory…

I need to be able to determine in code whether the element is already a widget or not…

My investmentGrid widget is created on #container with

 $('#container').investmentGrid()

I need to be able to determine elsewhere in the code if $(‘#container’) is already an investmentGrid

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-15T10:34:34+00:00Added an answer on May 15, 2026 at 10:34 am

    You can query the element’s jQuery.data() function, like so:

    if ($('#container').data('investmentGrid')) {
       ...
    }
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

http://jsfiddle.net/B2rdD/3/ I've Created 25 buttons using HTML and I have written jquery code such
I have written jQuery code, in files Main.html and ajax.php . The ajax.php file
I have written some jQuery code to use the slideUp animation when deleting rows
I have stolen/found/used/written and edited the following widget of jQuery for a auto-completing dropdown.
I have written jquery code to show description if I hover on a hyperlink.
This is the piece of code I have written: <html> <head> <script type=text/javascript src=jquery-min.js></script>
I have written some simple jquery code : function Generate(result, counter) { $(#ArchivesContent).append( <table
I have written a little jQuery in order to be able to upload a
Say I have a mobile web app written using JQuery Mobile, this app retrieves
I have written a site in Prototype but want to switch to jQuery. Any

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.