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Home/ Questions/Q 6253653
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T14:02:29+00:00 2026-05-24T14:02:29+00:00

I have written a method trial for button btnTrial1 : public void trial(object sender,

  • 0

I have written a method trial for button btnTrial1:

public void trial(object sender, EventArgs e, Button btn, TextBox txt, Label lbl)
{

}

In my application, i am generating more buttons and textboxes and labels dynamically through code and naming them sequentially like btnTrial2, txtTrial2, lblTrial2 then btnTrial3, txtTrial3, lblTrial3 and so on. Now i want to set trial as EventHandler for btnTrial2 then for btnTrial3 and so on.

So now when i call the method trial from btnTrial1, my parameters should be:

Public void (sender, e, btnTrail1, txtTrial1, lblTrial1)

But when i call the method trial from btnTrial2, my parameters should be:

Public void (sender, e, btnTrail2, txtTrial2, lblTrial2)

and so on…

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T14:02:30+00:00Added an answer on May 24, 2026 at 2:02 pm
    btnTrial1.YourEvent += (sender, args) => trial(sender, args,
            btnTrial1, txtTrial1, lblTrial1);
    btnTrial2.YourEvent += (sender, args) => trial(sender, args,
            btnTrial2, txtTrial2, lblTrial2);
    

    You mention “generating them dynamically” – that is fine, but if you are in a loop you will also need to watch out for the infamous “captured variable / loop” problem – notably, the variables “captured” must be inside the loop; for example:

    for(int i = 1 ; i <= 10 ; i++) {
        var btnTrial = ...
        var txtTrial = ...
        var lblTrial = ...
        btnTrial.YourEvent += (sender, args) => trial(sender, args,
            btnTrial, txtTrial, lblTrial);
    }
    

    (if, for example, btnTrial was declared outside the loop, bad things would happen)

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