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Home/ Questions/Q 7841043
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T16:00:44+00:00 2026-06-02T16:00:44+00:00

I have written a small piece of code: System out = null; out.out.println(Hello); This

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I have written a small piece of code:

 System out = null;
 out.out.println("Hello");

This is working fine and is printing “Hello” on the console.

Now in my program or my scope, there are two objects having the name out. One is the object of System and another is the object of PrintStream.

Why am I not getting a compiler error/ runtime error that says Duplicate local variable out.?

What am I missing here?

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  1. Editorial Team
    Editorial Team
    2026-06-02T16:00:45+00:00Added an answer on June 2, 2026 at 4:00 pm

    No, there’s just one object named out, the System-type local variable. The other is named out.out, it is not directly “in your scope”.

    There is no reason for this to cause a compile-time error.

    (BTW, calling static methods/referencing static fields via null references isn’t really good practice, it’s pretty confusing.)

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