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Home/ Questions/Q 4109328
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T21:46:56+00:00 2026-05-20T21:46:56+00:00

I have written an if statement in jQuery. My code: if($(‘#customer0’).checked()) { $(‘#shop’).fadeOut(); }

  • 0

I have written an if statement in jQuery.

My code:

if($('#customer0').checked())
{
  $('#shop').fadeOut();
}

else if($('#customer1').checked())
{
  $('#shop').fadeIn();
}

else ($('#customer2').checked())
{
  $('#shop').fadeOut();
};

When I have if (custmer0) and else (customer1) the fadeOut and fadeIn work good. But when it’s customer2 (that is else statement) it is not working? What is wrong?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T21:46:57+00:00Added an answer on May 20, 2026 at 9:46 pm

    else doesn’t take any parameters. The code below is more applicable:

    if($('#customer0').checked()) { $('#shop').fadeOut(); }
    else if($('#customer1').checked()) { $('#shop').fadeIn(); }
    else if($('#customer2').checked()) { $('#shop').fadeOut(); };
    
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