Question

I have written an xslt that reads some xml file names and does some operations on them.
I use a for-each to work them one-by-one. I have each path inside a parameter $path.

But now I would like to output the result of applying an external stylesheet to those files. I would write something like

<div> <something like xsl-transform($extern-xslt,$path)> </div>

to have the result tree of the transformation inside the main html output.
It is possible?

Answer 1

You can use the document() XPath function to load an external XML file. This returns a node-set which can be parsed with a <xml:apply-templates> call. Including an external stylesheet can be accomplished by using an <xsl:include> tag.

<xsl:include href="$external"/>
<xsl:apply-templates select="document($path)"/>

See also the documentation for document()