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Home/ Questions/Q 9116773
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T04:45:14+00:00 2026-06-17T04:45:14+00:00

I have written following code in nasm assembly for printing array element on scree.In

  • 0

I have written following code in nasm assembly for printing array element on scree.In this code there is no compilation error but I am getting garbage value on the screen.

section .data
num1: dd 10, 20, 30, 40, 50, 10, 20, 30, 40, 50,300
total: dd 0
msg :  dd "Value=%d",10,0

    section .text
        extern _printf
        global _main
    _main:
        push ebp
        mov ebp,esp
        mov ebx,num1 ;point bx to first number
        mov ecx,11     ;load count of numbers in ecx
        mov eax,0       
    loop:
        mov eax,[ebx]

        push msg
        call _printf



        add ebx,4
        sub ecx,1
        jnz loop

        mov esp,ebp
        pop ebp

        ret

Solution

section .data
num1: dd 10, 20, 30, 40, 50, 10, 20, 30, 40, 50,300
total: dd 0
msg :  dd "Value=%d",10,0

    section .text
        extern _printf
        global _main
    _main:
        push ebp
        mov ebp,esp
    mov eax,10
        mov ebx,num1 ;point bx to first number
        mov ecx,0 ;load 0

    loop:

    ;store the value because external function like printf modify the value
    push ebx
    push eax
    push ecx

        push DWORD [ebx]

        push msg
        call _printf
    add esp,8

    ;restore thses values
    pop ecx
    pop eax
    pop ebx
    inc ecx
    add ebx,4
    cmp ecx,eax
    jne loop



        mov esp,ebp
        pop ebp

        ret
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-17T04:45:16+00:00Added an answer on June 17, 2026 at 4:45 am

    I have figure out the solution of my problem.So I am posting here for other people

    section .data
    num1: dd 10, 20, 30, 40, 50, 10, 20, 30, 40, 50,300
    total: dd 0
    msg :  dd "Value=%d",10,0
    
        section .text
            extern _printf
            global _main
        _main:
            push ebp
            mov ebp,esp
        mov eax,10
            mov ebx,num1 ;point bx to first number
            mov ecx,0 ;load 0
    
        loop:
    
        ;store the value because external function like printf modify the value
        push ebx
        push eax
        push ecx
    
            push DWORD [ebx]
    
            push msg
            call _printf
        add esp,8
    
        ;restore thses values
        pop ecx
        pop eax
        pop ebx
        inc ecx
        add ebx,4
        cmp ecx,eax
        jne loop
    
    
    
            mov esp,ebp
            pop ebp
    
            ret
    
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