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Home/ Questions/Q 7675887
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T17:04:18+00:00 2026-05-31T17:04:18+00:00

I have written java code for generating json of my searched data from file.But

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I have written java code for generating json of my searched data from file.But its not generating exact JsonArray. Its like

[{"item":"1617"},{"item":"1617"}]

instead of

[{"item":"747"},{"item":"1617"}].

Here 1617 is last item which is fetched from file.

JSONArray ja = new JSONArray();
JSONObject jo = new JSONObject();

while (products.readRecord())
{
    String productID = products.get("user");
    int j = Integer.parseInt(productID);
    if(j == userId) {
        itemid = products.get("item");
        jo.put("item",itemid);
        ja.add(jo);
    }
}  

out.println(ja);
products.close();
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T17:04:20+00:00Added an answer on May 31, 2026 at 5:04 pm

    you are actually creating one jSONobject object to handle two objects, shouldn’t you need to create JSONObjects in the while loop? something like this, so every iteration in while loop will create a new JSONObject and add it to JSONArray

    JSONArray ja = new JSONArray();
    
    while (products.readRecord())
    {
        String productID = products.get("user");
        int j = Integer.parseInt(productID, 10);
    
        if(j == userId)
        {
             JSONObject jo = new JSONObject();
             itemid = products.get("item");
             jo.put("item", itemid);
             ja.add(jo);
        }
    
    }  
    
    out.println(ja);
    products.close();
    

    Extra:

    i am not sure how java does conversion for string to integer, but i think you should always specify radix when using parseInt so the strings like ’09’ will not be treated as octal value and converted to wrong value (atleast this is true in javascript :))

    Integer.parseInt(productID, 10);

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