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Editorial Team
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Asked: 2026-05-28T07:57:49+00:00

I have written php script for user login but instead of displaying the result

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I have written php script for user login but instead of displaying the result the whole script is being displayed.I have given a .php file link as an action for the login form.

I am using xampp with php and mysql running do I need anything else?

the code is :

<!DOCTYPE html>
<html lang="en">
<head>
  <meta charset="utf-8" />

  <!-- Always force latest IE rendering engine (even in intranet) & Chrome Frame 
       Remove this if you use the .htaccess -->
  <meta http-equiv="X-UA-Compatible" content="IE=edge,chrome=1" />

  <title>Ch</title>
  <meta name="description" content="education,India,College search in india,score evaluator" />
  <meta name="author" content="RAJATEJAS" />
  <meta name="viewport" content="width=device-width; initial-scale=1.0" />

  <!-- Replace favicon.ico & apple-touch-icon.png in the root of your domain and delete these references -->
  <link rel="shortcut icon" href="/favicon.ico" />
  <link rel="apple-touch-icon" href="/apple-touch-icon.png" />

  <style type = "text/css">
    user_login , input
    {
        display = inline;   
    }   
  </style>

</head>

<body>
  <div>
    <header>
      <h1>Ch</h1>
    </header>

    <nav>
      <p><a href="/">Home</a></p>
      <p><a href="/contact">Contact</a></p>
    </nav>

    <div class = "user_login_form">
        <form action = "chalo_login.php" method="post">
            <label>Username:</label><input id = "username" type = "text" name = "username" autofocus placeholder="Enter Username"/><br />
            <label>Password:</label><input id = "password" type = "password" name = "password" placeholder="Enter Password"/><br />
            <input name = "submit" type = "submit" value = "Login" />
        </form>   
    </div>


    <footer>
     <p>&copy; Copyright  by RAJATEJAS</p>
    </footer>
  </div>
</body>
</html>

<?php
    session_start();
    $_POST['username'];
    $_POST['password'];

    if ($username&&$password)
    {
        $connect = mysql_connect("localhost","root","");
        mysql_select_db("phplogin") or die("could not find database");
        $query = mysql_query(SELECT * FROM users WHERE username = "$username");
        $numrow = mysql_num_rows($query);
        if ($numrows !=0)
        {
            while ($row = mysql_fetch_assoc($query))
            {
                $dbusername = $row["username"];
                $dbpassword = $row["password"];
            }
            if($username == $dbusername && $password == $dbpassword)
            {
                echo "You are logged in! ;
                <a href ="member.php">Click here</a>";
                $_SESSION["username"] = $dbusername;

            }
            else
            {
                echo "Incorrect password";
            }
        }else{die("Account does not exists");}
    } 
    else 
    {
    die ("Please enter details");   
    }

?>
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1 Answer

  1. Editorial Team

    You’ve got a few errors in your code, but I don’t know if they’re what are causing your problems.

    Firstly in your CSS user_login should be #user_login to select elements with the ID “user_login”. Then, display = inline; should be display: inline;.

    In your PHP…

    $_POST['username'];
$_POST['password'];

    …doesn’t do anything. I think you should have

    $username = $_POST['username'];
$password = $_POST['password'];

    And as Ethan mentioned in the comments above, your quotation marks are messed up:

    echo "You are logged in! ;
<a href ="member.php">Click here</a>";

    …should probably be:

    echo "You are logged in! <a href =\"member.php\">Click here</a>";

    (Escape your quotation marks inside quotation marks using a backslash).

    Fix those errors and see if it works then…

    Also: as LeleDumbo says above, make sure the page is being loaded through Apache rather than opened as a file. The URL should begin with something like 127.0.0.1 or localhost. If not, just put 127.0.0.1 into your address bar and browse to your file in the list that appears.

    Another error- your SELECT statement needs to be a string:

    $query = mysql_query("SELECT * FROM users WHERE username = '$username'");
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