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Home/ Questions/Q 3359456
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T02:52:28+00:00 2026-05-18T02:52:28+00:00

I have written the following class: class myClass(object): def __init__(self): pass def foo(self, arg1,

  • 0

I have written the following class:

class myClass(object):
    def __init__(self):
        pass

    def foo(self, arg1, arg2):
        pp = foobar(self, arg1, arg2)
        if pp:
            return 42
        else
            return -666


    def foobar(self, arg1, arg2):
        if arg1 == arg2:
            return 42
        else:
            return None

The logic is nonsensical – ignore it. What I am trying to so is to call an instance method from another instance method – and I am getting a NameError. I originally thought that this was due to foo() calling foobar() before it had been defined – but switching the order of the function definitions in the script made no difference.

Does anyone what’s causing this error, and how to fix it?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T02:52:28+00:00Added an answer on May 18, 2026 at 2:52 am

    Python doesn’t scope code to the local class automatically; you need to tell it to.

    pp = self.foobar(arg1, arg2)
    

    http://docs.python.org/tutorial/classes.html

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