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Home/ Questions/Q 742563
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T08:45:44+00:00 2026-05-14T08:45:44+00:00

I have written this piece of code that splits a string and stores it

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I have written this piece of code that splits a string and stores it in a string array:-

String[] sSentence = sResult.split("[a-z]\\.\\s+");

However, I’ve added the [a-z] because I wanted to deal with some of the abbreviation problem. But then my result shows up as so:-

Furthermore when Everett tried to instruct them in basic mathematics they proved unresponsiv

I see that I lose the pattern specified in the split function. It’s okay for me to lose the period, but losing the last letter of the word disturbs its meaning.

Could someone help me with this, and in addition, could someone help me with dealing with abbreviations? For example, because I split the string based on periods, I do not want to lose the abbreviations.

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  1. Editorial Team
    Editorial Team
    2026-05-14T08:45:45+00:00Added an answer on May 14, 2026 at 8:45 am

    Parsing sentences is far from being a trivial task, even for latin languages like English. A naive approach like the one you outline in your question will fail often enough that it will prove useless in practice.

    A better approach is to use a BreakIterator configured with the right Locale.

    BreakIterator iterator = BreakIterator.getSentenceInstance(Locale.US);
    String source = "This is a test. This is a T.L.A. test. Now with a Dr. in it.";
    iterator.setText(source);
    int start = iterator.first();
    for (int end = iterator.next();
        end != BreakIterator.DONE;
        start = end, end = iterator.next()) {
      System.out.println(source.substring(start,end));
    }
    

    Yields the following result:

    1. This is a test.
    2. This is a T.L.A. test.
    3. Now with a Dr. in it.
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