Question

I have written this shell script as wrapper to a JAR file. The script launches the JAR without problem but completes without waiting for the JAR to finish its job.

#!/bin/bash

export WORK=/opt/conversion
export LOG=$WORK
export XMAIL=[e-mail]
export JAVA_BASE=/usr/java/jdk1.6.0_06
export JAVA_HOME=/usr/java/jdk1.6.0_06/bin
export JAR=$WORK/conversion.jar
export CLASSPATH=$JAVA_BASE/lib/tools.jar
export CLASSPATH=$CLASSPATH:$WORK/lib/ojdbc14.jar
export CLASSPATH=$CLASSPATH:$JAR

$JAVA_HOME/java -Xms256M -Xmx512M -classpath $CLASSPATH com.myapp.cam.conversion >>$WORK/job.out 2>&1 &

echo $! > $WORK/job.pid
mail -s "Conversion" $XMAIL < $WORK/user_message
exit 0

Is there a way to have the script wait on my JAR file to complete?

Thanks for your input.

Answer 1

You have a & at the end of the command:

$JAVA_HOME/java -Xms256M -Xmx512M -classpath $CLASSPATH com.myapp.cam.conversion >>$WORK/job.out 2>&1 &

which makes it run in background.

Remove the & to wait for the java process to complete before you proceed in the script.