Question

I have written this simple c code in microsoft visual c++ 2010.

   #include<stdio.h>
    #include<conio.h>
    void main()
    {
    char title[20], artist[30];
    int numtrack, price;
    char type;

    printf("Enter the title of CD \n");
    scanf("%s",title);
    printf("\nName of the artist \n");
    scanf("%s",artist);
    printf("\nEnter the type of CD(enter a for album and s for single)\n");
    scanf("%c",&type);
    printf("\n Enter the number of tracks \n");
    scanf("%d", &numtrack);
    printf("\n Enter the price of the cd \n");
    scanf("%d", &price);
    printf("%s\n%s\n%c\n%d\n%d\n",title, artist, type, numtrack, price);
    getch();
    }

It’s out put is

Enter the title of CD
ranjit

Name of the artist
mahanti

Enter the type of CD(enter a for album and s for single)

 Enter the number of tracks

4

 Enter the price of the cd
4
ranjit
mahanti


4
4

I can’t understand why it is not waiting for input for type variable? Can anybody explain this please? Thanks in advance.

Answer 1

Instead of

scanf("%c",&type);

you want

scanf(" %c",&type);

Otherwise, one of the newline characters from the previous string is going to be consumed as the type.