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Home/ Questions/Q 3754996
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T09:37:50+00:00 2026-05-19T09:37:50+00:00

I have written two versions of code. The first one works as expected and

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I have written two versions of code. The first one works as expected and print “Hi”. the second one gives me error that “block following this let is unfinished”

1st version

#light 

let samplefn() =
            let z = 2
            let z = z * 2
            printfn "hi"

samplefn()

2nd version

#light 

let samplefn() =
            let z = 2
            let z = z * 2           

samplefn()

Only difference is the printfn is absent in the second version. I am using Visual Studio 2010 as my IDE. I am very new to F# but this error seems very strange to me. I guess I am missing some very important concept. Please explain.

Edit: Also if I do it outside the function I get error even with the first version of code.

#light
let z = 2
let z = z * 2
printfn "Error: Duplicate definition of value z"
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-19T09:37:50+00:00Added an answer on May 19, 2026 at 9:37 am

    A let that is not at the top level (e.g. your indented ones) has to have a statement (actually an expression, as pst notes) called a “body” following the assignment. In the first example the body is printfn "hi", while the second example has no body. That’s what the compiler is complaining about.

    Note that in your function definitions the inner let expressions actually create nested scopes. That is, the let z = z * 2 actually creates a new value called z and binds to it the value of the outer z times 2, then uses it in the body of the let (which is the printfn in this case). A nested let will always have a body. It is the nesting which allows the seemingly duplicate definition.

    Since an outermost let does not need a body, the compiler thinks you’re trying to redefine z in the same scope, which is an error. You can use parentheses to tell the compiler how to properly interpret the last example:

    let z = 2
    (let z = z * 2
    printfn "z = %d" z)
    printfn "z = %d" z
    

    The above will print

    z = 4
    z = 2

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