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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T10:15:38+00:00 2026-05-16T10:15:38+00:00

I have wrote universal script to get all rows from Doctrine Table Models, but

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I have wrote universal script to get all rows from Doctrine Table Models, but if rows amount is too large, i get exception:

Cannot define NULL as part of query when defining 'offset'.

Running script:

$table = new JV_Model_StoreOrder();
$this->data['list'] = $table->getTable()->findAll()->toArray();

I understand from the error above is due to the large number of entries in the table (> 20 000). So I decided to make a paginator to break records on the pages of 100 pieces.

Could you help me, how can I do something like that:

...
$total_amount = $table->getTable()->count();
$this->data['list'] = $table->getTable()->offset(0)->limit(100)
->findAll()->toArray();
...
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  1. Editorial Team
    Editorial Team
    2026-05-16T10:15:38+00:00Added an answer on May 16, 2026 at 10:15 am

    Doctrine has it’s own Pagination component:

    • http://www.doctrine-project.org/documentation/manual/1_0/ru/utilities:pagination

    Example from Doctrine manual:

    // Defining initial variables
    $currentPage = 1;
    $resultsPerPage = 50;
    
    // Creating pager object
    $pager = new Doctrine_Pager(
          Doctrine_Query::create()
                ->from( 'User u' )
                ->leftJoin( 'u.Group g' )
                ->orderby( 'u.username ASC' ),
          $currentPage, // Current page of request
          $resultsPerPage // (Optional) Number of results per page. Default is 25
    );
    
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