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Home/ Questions/Q 659587
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T23:03:41+00:00 2026-05-13T23:03:41+00:00

I have WSGI middleware that needs to capture the HTTP status (e.g. 200 OK

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I have WSGI middleware that needs to capture the HTTP status (e.g. 200 OK) that inner layers of middleware return by calling start_response. Currently I’m doing the following, but abusing a list doesn’t seem to be the “right” solution to me:

class TransactionalMiddlewareInterface(object):
    def __init__(self, application, **config):
        self.application = application
        self.config = config

    def __call__(self, environ, start_response):
        status = []

        def local_start(stat_str, headers=[]):
            status.append(int(stat_str.split(' ')[0]))
            return start_response(stat_str, headers)

        try:
            result = self.application(environ, local_start)

        finally:
            status = status[0] if status else 0

            if status > 199 and status 

The reason for the list abuse is that I can not assign a new value to the parent namespace from within a wholly contained function.

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  1. Editorial Team
    Editorial Team
    2026-05-13T23:03:41+00:00Added an answer on May 13, 2026 at 11:03 pm

    You can assign the status as an injected field of local_start function itself rather than using status list. I used something similar, works fine:

    class TransactionalMiddlewareInterface(object):
        def __init__(self, application, **config):
            self.application = application
            self.config = config
    
        def __call__(self, environ, start_response):
            def local_start(stat_str, headers=[]):
                local_start.status = int(stat_str.split(' ')[0])
                return start_response(stat_str, headers)
            try:
                result = self.application(environ, local_start)
            finally:
                if local_start.status and local_start.status > 199:
                    pass
    
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