Question

I have XML like

<root>
    <a>One</a>
    <a>Two</a>
    <b>Three</b>
    <c>Four</c>
    <a>Five</a>
    <b>
        <a>Six</a>
    </b>
</root>

and need to select the last occurrence of any child node name in root. In this case, the desired resulting list would be:

<c>Four</c>
<a>Five</a>
<b>
    <a>Six</a>
</b>

Any help is appreciated!

Answer 1

XSLT based solution:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
    <xsl:output method="xml" indent="yes" omit-xml-declaration="yes"/>
    <xsl:strip-space elements="*"/>

    <xsl:template match="root/*">
        <xsl:variable name="n" select="name()"/>
        <xsl:copy-of
            select=".[not(following-sibling::node()[name()=$n])]"/>
    </xsl:template>
</xsl:stylesheet>

Produced output:

<c>Four</c>
<a>Five</a>
<b>
   <a>Six</a>
</b>

Second solution (you can use it as single XPath expression):

<xsl:template match="/root">
    <xsl:copy-of select="a[not(./following-sibling::a)]
        | b[not(./following-sibling::b)]
        | c[not(./following-sibling::c)]"/>
</xsl:template>