Question

I have XML like this: (this is the soup variable)

<?xml version="1.0" encoding="utf-8"?>
<results>
 <status code="ok">
 </status>
 <principal-list>
  <principal account-id="1013353221" has-children="false" is-hidden="false" is-primary="false" principal-id="1013353225" training-group-id="" type="user">
   <name>
    First Last
   </name>
   <login>
    first.last
   </login>
   <email>
    [e-mail]
   </email>
   <display-uid>
    first.last
   </display-uid>
  </principal>
  <principal account-id="1013353221" has-children="false" is-hidden="false" is-primary="false" principal-id="1115269931" training-group-id="" type="user">
   <name>
    First Last
   </name>
   <login>
    first.last
   </login>
   <email>
    [e-mail]
   </email>
   <display-uid>
    first.last
   </display-uid>
  </principal>
 </principal-list>
</results>

I’ve tried this code:

loginlist = [el.string for el in soup.findAll('login')]
for entry in loginlist:
    print entry

It returns:

first.last

for each of the users.

I want to also find the principal-id for the nested login

My output would look like:

`'first.last', '1013353225'`
`'first.last', '1115269931'`

Answer 1

Look for the <principal> elements instead:

for principal in soup.findAll('principal'):
    login = principal.find('login')
    if login is None:
        continue
    print principal['principal-id'], login.string