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Home/ Questions/Q 3976962
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T04:52:01+00:00 2026-05-20T04:52:01+00:00

I have XML with the following structure, for example <root> <node flag=false/> <node flag=true/>

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I have XML with the following structure, for example

<root>
    <node flag="false"/>
    <node flag="true"/>
    <node flag="false"/>
    <node flag="false"/>
    <node flag="true">
        <node flag="false"/>
        <node flag="true"/>
        <node flag="false"/>
        <node flag="true"/>
    </node>
    <node flag="true"/>
    <node flag="false">
        <node flag="false"/>
        <node flag="true"/>
        <node flag="false"/>
        <node flag="true"/>
    </node>
    <node flag="false"/>
</root>

All children have name “node”. What I need is to get an XMLList (or XML, no matter), with the same hierarchy, but containing only nodes with the flag “true”.

The result I need for my example is:

<root>
    <node flag="true"/>
    <node flag="true">
        <node flag="true"/>
        <node flag="true"/>
    </node>
    <node flag="true"/>
</root>

Is there any nice way to do this using e4x (without iterating through loop)? I tried to do the following:
xml.node.(@flag==”true”), but the result in this case is:

<root>
        <node flag="true"/>
        <node flag="true">
            <node flag="false"/> <!--need to kill this node-->
            <node flag="true"/>
            <node flag="false"/> <!--need to kill this node-->
            <node flag="true"/>
        </node>
        <node flag="true"/>
    </root>

Any ideas? Thank you!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T04:52:02+00:00Added an answer on May 20, 2026 at 4:52 am

    Here a one liner in e4x as you ask :

    xml..node.((@flag=="false") && (delete parent().children()[valueOf().childIndex()]))
    

    it delete the node to the current XML so pay attention to have a copy of your current XML.

    By the way you should know that e4x just do a loop under the hood, and that one liner will not be faster than a custom loop.

    var xml:XML=<root>
        <node id="1" flag="false"/>
        <node id="2" flag="true"/>
        <node id="3" flag="false"/>
        <node id="4" flag="false"/>
        <node id="5" flag="true">
            <node id="5.1" flag="false"/>
            <node id="5.2" flag="true"/>
            <node id="5.3" flag="false"/>
            <node id="5.4" flag="true"/>
        </node>
        <node id="6" flag="true"/>
        <node id="7" flag="false">
            <node id="7.1" flag="false"/>
            <node id="7.2" flag="true"/>
            <node id="7.3" flag="false"/>
            <node id="7.4" flag="true"/>
        </node>
        <node id="8" flag="false"/>
    </root>
    
    trace("-- before --")
    trace(xml.toXMLString())
    
    xml..node.((@flag=="false") && (delete parent().children()[valueOf().childIndex()])) 
    
    trace("\n-- after --")
    trace(xml.toXMLString())
    
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