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Home/ Questions/Q 7848623
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T18:16:23+00:00 2026-06-02T18:16:23+00:00

I haven’t been able to find an example that does something similar to what

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I haven’t been able to find an example that does something similar to what I want, that is, replace:

% with %25

& with %26

/ with %2F

# with %23

” with space

\ with space

For the reference I’m using GWT with String.replaceAll, but I’m asking about Javascript since that is what it gets translated to anyway. I know about (component) URI encoding, but it’s not what I’m after, I only need these characters.

Later edit: I’m looking for a way to do it in one or two regexes, right now it’s done as this:

splits[i].replaceAll("%", "%25").replaceAll("&", "%26").replaceAll("/","%2F").replaceAll("#", "%23").replaceAll("\"", "").replaceAll("\\\\", " ");

but this seems ugly to me.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-02T18:16:25+00:00Added an answer on June 2, 2026 at 6:16 pm

    (This is for JavaScript, which is the language you asked about. Note that it will be fairly different in Java.)

    In JavaScript, this is trivial using replace with a regular expression and passing in a function:

    var str = "testing % & / # \" \\";
    var result = str.replace(/[%&\/#"\\]/g, function(m) {
        return (m === '"' || m === '\\') ? " " : "%" + m.charCodeAt(0).toString(16);
    });
    

    Live example | source

    If you don’t mind scanning the string twice rather than once, it can look a bit simpler (though not enough that I think it’s worth it):

    var str = "testing % & / # \" \\";
    var result = str.replace(/["\\]/g, " ").replace(/[%&\/#]/g, function(m) {
        return "%" + m.charCodeAt(0).toString(16);
    });
    

    …because we can do the " and \ replacement separately and get rid of the check for what we matched. Live example | source

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