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Home/ Questions/Q 6911239
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T08:55:36+00:00 2026-05-27T08:55:36+00:00

I haven’t been able to reproduce this problem with another script, so please run

  • 0

I haven’t been able to reproduce this problem with another script, so please run this script:
http://jsfiddle.net/kz4k7/

As you can see at line 154-157:

for (myKey in v){
    console.log("v["+myKey +"] = "+v[myKey]); 
}
console.log(v);

you would expect the first three lines to output the same as the last line.
However I get this result in chrome:
enter image description here

If I remove the solveTriangle(v) at line 158, the console.log(v); works perfectly fine. It also works if I print a cloned version of the object v to the console.

Note: This isn’t finished at all, I just want to know why chrome does this. I also don’t want to explain “why have you done it that way?” and other questions unrelated to this bug.

Edit:

This is also the behavior in Safari.

Firefox + firebug screenshot:

enter image description here

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  1. Editorial Team
    Editorial Team
    2026-05-27T08:55:37+00:00Added an answer on May 27, 2026 at 8:55 am

    console.log shows what the object contains when you open it (by clicking the arrow), not when it was logged. Frankly, your code it pretty verbose and a bit messy with lots of commented-out code, but it seems like you’re indeed modifying the object after logging it.

    You can confirm this log behaviour with the following simplified test: http://jsfiddle.net/e7Gvn/.

    var o = {
        a: 1,
        b: 2
    };
    
    console.log( JSON.stringify(o) ); // force string logging, which doesn't change
    
    console.log(o); // open the object and you'll see that `c = 3`...
    o.c = 3;        // ... even though it was only set here
    
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