Question

I haven’t done any geometry in such a long time that I cannot figure out how to do this.

I created this method:

public Polygon getHex(int posX, int posY) {
        Polygon hex = new Polygon();
        for (int i = 0; i < 6; i++) {
            hex.addPoint((int) (posX + (50 * Math.cos(i * 2 * Math.PI / 6))),
                    (int) (posY + (50 * Math.sin(i * 2 * Math.PI / 6))));
        }
        return hex;
    }

This creates a equilateral Hexagon like this:

  _
 / \
 \_/

I need a rotated, equilateral hexagon like this:

   /\
  |  |
   \/ 

Can anybody help me remember math? Thank you

Answer 1

Change i * 2 to (1 + i * 2), that will rotate all of your points by pi/6, which should do the trick!