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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T06:19:44+00:00 2026-05-13T06:19:44+00:00

I heard people say exception handling is a bit expensive because of the stack

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I heard people say exception handling is a bit expensive because of the stack unwinding.

I don’t get something, the stack unwinding happens whether I throw an exception and whether I use “return”. So where is the difference?

If for example I get a memory problem that I can’t handle – the only option is to stop the function till the I reach the area where the problem should be handled or notified. So what’s my other option for throwing an exception?

I can use “return” instead of throwing exception, but then it’s the same.
I know stack unwinding can go even six stacks back, but so checking return value and “return” combined.

An explanation will be welcomed.

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  1. Editorial Team
    Editorial Team
    2026-05-13T06:19:44+00:00Added an answer on May 13, 2026 at 6:19 am

    When you use a return, the stack is “unwound” unconditionally, which can conceptually be as simple as executing a single “ret” machine code instruction. Under exceptions, the stack unwinding has to search for a suitable exception handler, which is a far more complex task. The exception path also has the task of constructing and probably copying the exception object, which may not be trivial.

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