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Home/ Questions/Q 6085779
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T11:40:39+00:00 2026-05-23T11:40:39+00:00

I hope I’m not just making a stupid mistake, but For some reason, the

  • 0

I hope I’m not just making a stupid mistake, but For some reason, the following code doesn’t work. The only thing that happens is it logs “ready” in the console, but not anything within the .click

Javascript:

var Photobooth = (function (){
var api = {};

var init = function(){
    form_ready();

};


var form_ready = function(){
    console.log("ready");
    $('#btn-signin').click(function(e){


        e.preventDefault();
        console.log('click');

        $.ajax({
                type: 'POST',
                url: "entertainment/photobooth/signin/action/",
                data:$(this).serialize(),
              success: function(){
                $(this).addClass("done");
              }
            });

    });
};



init();
return api;
})();

HTML:

<a id="btn-signin" href="##">SIGN IN </a>

THE SOLUTION: Normally, I put my JS code at the end of the document, before the closing body… In this case I had to put it in the beginning and forgot to put the document.ready, so it works now. Thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T11:40:40+00:00Added an answer on May 23, 2026 at 11:40 am

    You need the document.ready wrapper:

    var Photobooth = $(function (){...
      ....
      init();
      return api;
    });
    
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