Question

I hope someone could give me a general direction on this problem:

The starting point is an array of ids of db records.

array ids = [45,23,14,7];

Those records have some columns, i.e.

id,price,rating
7,$5.00,5
14,$2.00,4
23,$5.00,2
45,$5.00,5

What I would need is

1. the items with max(price) (or something equivalent).
2. if there is more than one item with the same price, get the ones with max(rating) (or something equivalent).
3. Finally, if there is still more than one item, take the one that comes first in the array.

I’m particularly stuck with point 3. Is there a way to do that in (My)SQL, or should I do that in code?

Thank you for your reading.

Answer 1

In addition to the answer by @jasonlfunk you can add an extra order clause to take into account your array as well:

SELECT * FROM table WHERE id IN (45,23,14,7) ORDER BY price DESC, rating DESC, FIELD(id,45,23,14,7) ASC LIMIT 1