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Home/ Questions/Q 6091445
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T12:19:43+00:00 2026-05-23T12:19:43+00:00

I implement this interleave method in java but it doesn’t work properly. Where is

  • 0

I implement this interleave method in java but it doesn’t work properly. Where is my error?
I would like to mix 2 String List.

["a","b","c"]
["1","2","3","4"]

result should be = [a, 1, b, 2, c, 3, 4]
but I got only [a, 1, b, 2, c, 3].

public static List<String> interleave(List<String> list1,List<String>list2){
    List<String> result= new ArrayList<String>();

    for(int i=0; i<list1.size(); i++){
        result.add(list1.get(i));
        result.add(list2.get(i));
    }
    return result;
}

many thanks in advance.

regards,
koko

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  1. Editorial Team
    Editorial Team
    2026-05-23T12:19:43+00:00Added an answer on May 23, 2026 at 12:19 pm

    The error is that you’re only looking at list1.size() whereas in your case the second list is longer than the first.

    You should quite possibly use the iterators instead:

    Iterator<String> iterator1 = list1.iterator();
    Iterator<String> iterator2 = list2.iterator();
    
    while (iterator1.hasNext() || iterator2.hasNext())
    {
        if (iterator1.hasNext())
        {
            result.add(iterator1.next());
        }
        if (iterator2.hasNext())
        {
            result.add(iterator2.next());
        }
    }
    

    You could just use the sizes, finding the minimum one and then filling in the rest afterwards, but the code’s likely to get ugly. Also, the above code is generalizable to any two Iterable<String> values, not just List<String>.

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