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Home/ Questions/Q 8395211
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T20:14:36+00:00 2026-06-09T20:14:36+00:00

I implemented a file cache to load small images for a long grid view.

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I implemented a file cache to load small images for a long grid view. After scrolling a while, I get a lot of libcore.io.ErrnoException: open failed: EMFILE (Too many open files)

How do I avoid this? This is the code to read one bitmap:

File fullCacheDir = new File(Environment.getExternalStorageDirectory().toString(), cacheDir);
File file = new File(fullCacheDir.toString(), fileName);

if (!file.exists()) {
    return null;
}

Bitmap bm = BitmapFactory.decodeFile(file.toString());

This is to save one bitmap:

FileOutputStream outputStream = new FileOutputStream(fileUri);
bitmap.compress(Bitmap.CompressFormat.JPEG, 100, outputStream);
outputStream.flush();
outputStream.close();
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T20:14:37+00:00Added an answer on June 9, 2026 at 8:14 pm

    Any chance your close() call isn’t being reached due to an exception? I generally code like this:

    try {
      new FileOutputStream(fileUri);
      bitmap.compress(Bitmap.CompressFormat.JPEG, 100, outputStream);
      outputStream.flush();
    } finally {
      try {
        outputStream.close();
      } catch (Exception ignored) {
        // ignore exceptions generated by close()
      }
    }
    

    I couldn’t see anything obviously wrong with the first code fragment.

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