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Home/ Questions/Q 6798911
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T18:47:11+00:00 2026-05-26T18:47:11+00:00

I implemented myPrintf function: int myPrintf(const char* format,…) { va_list args; va_start(args, format); int

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I implemented myPrintf function:

int myPrintf(const char* format,...)
{
    va_list args;
    va_start(args, format);
    int ret = vprintf (format, args);
    fflush(stdout);
    va_end (args);
    return ret;
}

When I run the function with format = “%ld,%ld”
and the args representation as set of chars is 78,97,188,0,0,0,0,0,120,10,227,5,0,0,0,0
the output printed to stdout is 12345678,0.Instead of 12345678,98765432.
What could be the problem?And how could it be solved?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T18:47:11+00:00Added an answer on May 26, 2026 at 6:47 pm

    Because, like on ideone, your longs are 32 bits
    http://ideone.com/jjafU

    If you use "%lld" for 64-bit values, it works as you expect
    http://ideone.com/BYTaa

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