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Home/ Questions/Q 4233398
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T02:12:55+00:00 2026-05-21T02:12:55+00:00

I initialize a php array named $present, the purpose of this array is to

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I initialize a php array named $present, the purpose of this array is to hold the value of 1 if a name is present or zero if the name is absent. i have a name array of size 10. below is the code mentioned, but it is not working.

$present = Array();
for($i=0;$i<=10;$i++){
    if(!isset($present[$name[$i]])) {
       $present[$name] = 1;
     }
     else echo $present[$name[$i]];
}

i have also tried this :

$present = Array();
    for($i=0;$i<=10;$i++){
        if(empty($present[$name[$i]])) {
           $present[$name] = 1;
         }
         else echo $present[$name[$i]];
    }

please help thanks!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-21T02:12:56+00:00Added an answer on May 21, 2026 at 2:12 am

    I think this may be what you are looking for. You’re missing the $i when setting it to 1.

    $present = array();
    for($i=0;$i<=10;$i++){
        if(!isset($present[$name[$i]])) {
           $present[$name[$i]] = 1;
         }
         else echo $present[$name[$i]];
    }
    
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