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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T05:21:36+00:00 2026-05-12T05:21:36+00:00

I intend to call a function whenever m_logger<<hello<<world is called. m_logger is of type

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I intend to call a function whenever m_logger<<"hello"<<"world" is called. m_logger is of type ofstream.

So i decide to overload << with following signature

friend ofstream& operator<<(ofstream &stream,char *str);

However the vc compiler gives following error:

error C2666: ‘operator <<‘ : 6 overloads have similar conversions

Is there anyother way to achieve this, my objective is to divert all the write operation to ofstream object to different function?

Creating an object of my own calss works for me, however how can i make it work like normal ofstream object which typecasts all system defined types into strings or char*. i know one approach would be to overload the operator for each and every type but is there a cleaner approach

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  1. Editorial Team
    Editorial Team
    2026-05-12T05:21:37+00:00Added an answer on May 12, 2026 at 5:21 am

    The problem is that ofstream is already overloaded this way. If you make mlogger of a new type holding an ofstream, then you can do this:

    class mlogger_t {
    public:
        ofstream stream;
        ...
    }
    
    mlogger_t& operator<<(mlogger_t& stream, const string& str) {
        stream.stream << str;
        ...
    }
    
    //EDIT: here is how to make this work for other types too using templates:
    template<typename T> mlogger_t& operator<<(mlogger_t& stream, T val) {
        stream.stream << val;
    }
    
    ...
    
    mlogger_t mlogger;
    
    mlogger << "foo";
    

    Also, you should definitely use a const string& (as I did in this example) rather than a C-style string. If you really need it to be C-style, at least use const char *.

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