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Home/ Questions/Q 6132059
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T17:03:15+00:00 2026-05-23T17:03:15+00:00

I invoked a php file by exec() doing this : <?php $cmd = php

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I invoked a php file by exec() doing this :

<?php
$cmd = "php -q nah.php";
exec($cmd);
echo "lalal";
?>

and the nah.php has this :

<?php
echo "yaya";
sleep(3);
?>

It does sleep for 3 seconds but the file can echo out to the command.
How can I do echo the output from nah.php

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T17:03:15+00:00Added an answer on May 23, 2026 at 5:03 pm

    If you want to capture the output of another process, then you can use backticks

    $output=`command line`;
    

    or capture it with exec()

    exec('command line', $output);
    

    However, both of these techniques only give the output when the external process has run to completion. If you want to grab the output as it happens, you can use popen (or proc_open for more control), e.g. something like this

    $handle = popen('command line 2>&1', 'r');
    while (!feof($handle))
    {
        $read = fread($handle, 2096);
        echo $read;
    }
    pclose($handle);
    

    The 2>&1 at the end of the command line is a handy idiom if running within a shell like bash. It redirects stderr to stdout, so any errors the command generates will be returned to PHP. There are more advanced ways to capture stderr, this just makes it easy.

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