Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 3795074
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 19, 20262026-05-19T13:01:41+00:00 2026-05-19T13:01:41+00:00

I just asked a similar question , but then I realized I actually need

  • 0

I just asked a similar question, but then I realized I actually need something else. Since that question already has two answers, I do not want to edit my question. So here is what I actually need:


I want to detect whether a subrange of an array contains null references only. Somehow like this:

public static <T> boolean nullReferencesOnly
(T[] array, int fromInclusive, int toExclusive)
{
    for (int i = fromInclusive; i < toExclusive; ++i)
    {
        if (array[i] != null) return false;
    }
    return true;
}

Is there a method like this in the Java library so I don’t have to manually loop over the array?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-19T13:01:41+00:00Added an answer on May 19, 2026 at 1:01 pm
    Collections.frequency(Arrays.asList(array), null) == array.length
    

    For a range, SLaks has already suggested .subList(from, to) in his answer.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

In another question , I asked something similar but I ended up just posting
Someone else has already asked a somewhat similar question: Validate an Xml file against
I've already asked a very similar question but that was using javascript/php - i've
I already asked a similar question but this one is a bit different/specific: I'm
I asked a similar question last week but did not get an answer that
I saw that a similar question was asked before, but I don't understand another
I asked a similar question yesterday that was specific to a technology, but now
I know this is a similar question to one already asked, but I was
There's probably someone else who asked a similar question, but I didn't take much
Sorry, I've asked a similar question but I'm already suffering 3 days dealing with

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.