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Home/ Questions/Q 560825
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T12:23:06+00:00 2026-05-13T12:23:06+00:00

I just call this function on a button click. I also want to know

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I just call this function on a button click.
I also want to know in which event of FileUpload I can call this function.

 Function upload() As Boolean
        Dim img As FileUpload = CType(imgUpload, FileUpload)
        imgByte = Nothing
        If img.HasFile AndAlso Not img.PostedFile Is Nothing Then
            Dim File As HttpPostedFile = imgUpload.PostedFile
            imgByte = New Byte(File.ContentLength - 1) {}
            File.InputStream.Read(imgByte, 0, File.ContentLength)
        End If
        Dim strImagePath As String = imgUpload.FileName
        imgUpload.PostedFile.SaveAs(Server.MapPath("..\Temporary\" + strImagePath))
        imgLogo.ImageUrl = Server.MapPath("..\Temporary\" + strImagePath)
        imgLogo.DataBind()
    End Function

Even after setting the url, image is not showing.I am sure that image file is created on the server and the path specified is right.

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  1. Editorial Team
    Editorial Team
    2026-05-13T12:23:06+00:00Added an answer on May 13, 2026 at 12:23 pm

    Try to use your relative path, as needed to your image to be read from your browser:

    imgLogo.ImageUrl = "../Temporary/" + strImagePath
    
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