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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T09:38:07+00:00 2026-05-15T09:38:07+00:00

I just deployed an application to a new server, and although I’m using virtualenv,

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I just deployed an application to a new server, and although I’m using virtualenv, I had to install a new environment on the production server, which has a different architecture.

Anyway, I received no TemplateSytaxErrors in development, but on the production server, I get:

Exception Type:     TemplateSyntaxError
Exception Value:    Caught SyntaxError while rendering: invalid syntax (views.py, line 25)

The offending line is:

{% url admin:password_change as password_change_url %}

Upon removing that line, the TemplateSyntaxError hops to the next line that has a colon in it (and lets other template tags work fine).

So my question is this: is there some discrepancy in versions of Python/Django that would allow or disallow the namespacing syntax?

The template tags are in django-grappelli (http://code.google.com/p/django-grappelli/), so I’d rather not go through their code and rewrite all the template tags.

Development server:

  • 32-bit Debian
  • Python 2.5.5
  • Django 1.2.1

Production server:

  • 64-bit CentOS
  • Python 2.4.3
  • Django 1.2.1

Any ideas?

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  1. Editorial Team
    Editorial Team
    2026-05-15T09:38:08+00:00Added an answer on May 15, 2026 at 9:38 am

    On closer inspection, I realized this wasn’t the offending line, even though it was highlighted in the traceback:

    {% url admin:password_change as password_change_url %}
    

    The line was actually in my views.py, where I used the ternary operator ("this" if condition else "that"). Little did I know, this syntax is only supported in Python 2.5 and up.

    Problem solved.

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