Question

I just executed this code example:

int *i = (int*) malloc( sizeof(int) );
printf( "%p, %p\n", &i , i );

and this is what I got:

0x7fff38fed6a8, 0x10f7010

So I wonder why is the second address shorter than the first one?

Answer 1

i is on the stack, while the chunk of memory it points to is in the heap. On your platform these are two very different areas of memory and it just so happens the heap addess is relatively low, numerically, so it has a lot of leading zeroes which are not shown, i.e.

&i = 0x7fff38fed6a8; // stack
 i = 0x0000010f7010; // heap