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Home/ Questions/Q 6801999
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Editorial Team
  • 0
Editorial Team
Asked: May 26, 20262026-05-26T19:10:11+00:00 2026-05-26T19:10:11+00:00

I just found myself a little bit surprised being unable to simply use a

  • 0

I just found myself a little bit surprised being unable to simply use a

std::unordered_set<std::array<int, 16> > test;

because there does not seem to be a std::hash specialization for std::arrays. Why is that? Or did I simply not find it? If there is indeed none, can the following implementation attempt be simplified?

namespace std
{
    template<typename T, size_t N>
    struct hash<array<T, N> >
    {
        typedef array<T, N> argument_type;
        typedef size_t result_type;

        result_type operator()(const argument_type& a) const
        {
            hash<T> hasher;
            result_type h = 0;
            for (result_type i = 0; i < N; ++i)
            {
                h = h * 31 + hasher(a[i]);
            }
            return h;
        }
    };
}

I really feel this should somehow be part of the standard library.

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  1. Editorial Team
    Editorial Team
    2026-05-26T19:10:11+00:00Added an answer on May 26, 2026 at 7:10 pm

    I’m not sure why the standard library hasn’t included this, but Boost has hashing for all sorts of things made up from hashable types. The key function for this is hash_combine, which you are welcome to copy from boost/functional/hash/hash.hpp.

    Using hash_combine, Boost derives a range_hash (just combining the hashes of a each element of a range), as well as pair and tuple hashers. The range_hash in turn can be used to hash any iterable container.

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