Question

I just started learning php last week and I am trying to populate values of a drop down list in my html form from mysql database. the dropdown shows but it only shows “choose” as an option. what am I doing wrong, any help would be march appreciated. Below is the problem part of my code.

<form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>">

 <?php
  require_once('connectvars.php');
  $dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME);
  $query = "SELECT event_id, event_name FROM events";

  $results= mysqli_query( $dbc, $query);

  $options="";

 while ($row=mysql_fetch_array($result)) {

 $id=$row["event_id"];
 $event=$row["event_name"];
 $options ="<OPTION VALUE=\"$id\">".$event;
 } 
?>


 <SELECT NAME=eventid>
<OPTION VALUE=0>Choose
  <?php echo $options ?>
 </SELECT> 
</form>

Answer 1

This is the mysql-driver solution.

<form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>">
<?php
    require_once('connectvars.php');
    $dbc = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);
    $db = mysql_select_db(DB_NAME);
    $results= mysql_query("SELECT event_id, event_name FROM events");
?>
<select name="eventid">
    <option value="0">Choose</OPTION>
    <?php 
        while($row = mysql_fetch_array($results)) {
            echo '<option value="'.$row['event_id'].'">'. $row['event_name'].'</option>';
        }
    ?>
</select> 
</form>