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Editorial Team
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Asked: 2026-05-15T09:30:43+00:00

I just started playing with Django today and so far am finding it rather

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I just started playing with Django today and so far am finding it rather difficult to do simple things. What I’m struggling with right now is filtering a list of status types. The StatusTypes model is:

class StatusTypes(models.Model):
    status = models.CharField(max_length=50)
    type = models.IntegerField()
    def __unicode__(self):
        return self.status
    class Meta:
        db_table = u'status_types'

In one admin page I need all the results where type = 0 and in another I’ll need all the results where type = 1 so I can’t just limit it from within the model. How would I go about doing this?

EDIT: I should have been a bit more clear. I have a model “Unit” which has a foreign key to to StatusTypes. The models are as follows:

class StatusTypes(models.Model):
    status = models.CharField(max_length=50)
    type = models.IntegerField()
    def __unicode__(self):
        return self.status
    class Meta:
        db_table = u'status_types'

class Unit(models.Model):
    name = models.CharField(unique=True, max_length=50)
    status = models.ForeignKey(StatusTypes, db_column='status')
    note = models.TextField()
    date_added = models.DateTimeField()
    def __unicode__(self):
        return self.name
    class Meta:
        db_table = u'units'

So now in the admin page for the unit model I want to limit the status to only those with type = 1. Based off of lazerscience response below I tried the following code:

from inv.inventory.models import Unit
from django.contrib import admin

class UnitAdmin(admin.ModelAdmin):
    def queryset(self, request):
        qs = super(UnitAdmin, self).queryset(request)
        return qs.filter(type=0)

admin.site.register(Unit, UnitAdmin)

But, it didn’t change the select box at all. I also tried printing the value of qs and nothing was outputted to my terminal so I’m wondering if I have to some how call queryset?

EDIT 2: It might not have been clear that I want to filter this for the status dropdown that is on the create page for the Unit model.

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1 Answer

  1. Editorial Team

    EDIT:

    It turns out that ModelAdmin.formfield_for_foreignkey was the right answer in this situation:
    http://docs.djangoproject.com/en/dev/ref/contrib/admin/#django.contrib.admin.ModelAdmin.formfield_for_foreignkey

    PREVIOUS ANSWER:

    Take a look at the list_filter attribute of ModelAdmin. That sounds more like what you want to me since it will create a nice interface for filtering on different criteria rather than arbitrarily restricting your queryset.

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