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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T13:44:25+00:00 2026-05-12T13:44:25+00:00

I just started playing with lambdas and Linq expression for self learning. I took

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I just started playing with lambdas and Linq expression for self learning. I took the simple factorial problem for this. with the little complex scenario where find the factorial for given n numbers (witout using recursive loops).

Below the code i tried. But this is not working.

public void FindFactorial(int range)
{

    var res = Enumerable.Range(1, range).Select(x => Enumerable.Range(0, x).Where(y => (y > 1)).Select(y => y * (y-1)));            
    foreach (var outt in res)
        Console.WriteLine(outt.ToString());

}

this is the procedure i used

  • loop through the numbers 1 to n — Enumerable.Range(1, range).
  • select each number x and again loop them upto x times (instead of
    recursion)
  • and select the numbers Where(y => (y > 1)) greater than 1 and multiply that with
    (y-1)

i know i messed up somewhere. can someone tell me whats wrong and any other possible solution.

EDIT:

i am going to let this thread open for some time… since this is my initial steps towards lambda.. i found all the answers very useful and informative.. And its going to be fun and great learning seeing the differnt ways of approaching this problem.

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  1. Editorial Team
    Editorial Team
    2026-05-12T13:44:25+00:00Added an answer on May 12, 2026 at 1:44 pm

    Currently there’s no recursion – that’s the problem. You’re just taking a sequence of numbers, and projecting each number to “itself * itself-1”.

    The simple and inefficient way of writing a factorial function is:

    Func<int, int> factorial = null; // Just so we can refer to it
    factorial = x => x <= 1 ? 1 : x * factorial(x-1);
    
    for (int i = 1; i <= range; i++)
    {
        Console.WriteLine(factorial(i));
    }
    

    Typically you then get into memoization to avoid having to repeatedly calculate the same thing. You might like to read Wes Dyer’s blog post on this sort of thing.

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