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Home/ Questions/Q 9193061
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T21:04:19+00:00 2026-06-17T21:04:19+00:00

I just started tinkering with Ruby earlier this week and I’ve run into something

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I just started tinkering with Ruby earlier this week and I’ve run into something that I don’t quite know how to code. I’m converting a scanner that was written in Java into Ruby for a class assignment, and I’ve gotten down to this section:

if (Character.isLetter(lookAhead))
{      
    return id();
}

if (Character.isDigit(lookAhead))
{
    return number();
}

lookAhead is a single character picked out of the string (moving by one space each time it loops through) and these two methods determine if it is a character or a digit, returning the appropriate token type. I haven’t been able to figure out a Ruby equivalent to Character.isLetter() and Character.isDigit().

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  1. Editorial Team
    Editorial Team
    2026-06-17T21:04:21+00:00Added an answer on June 17, 2026 at 9:04 pm

    Use a regular expression that matches letters & digits:

    def letter?(lookAhead)
      lookAhead.match?(/[[:alpha:]]/)
    end
    
    def numeric?(lookAhead)
      lookAhead.match?(/[[:digit:]]/)
    end
    

    These are called POSIX bracket expressions, and the advantage of them is that unicode characters under the given category will match. For example:

    'ñ'.match?(/[A-Za-z]/)     #=> false
    'ñ'.match?(/\w/)           #=> false
    'ñ'.match?(/[[:alpha:]]/)  #=> true
    

    You can read more in Ruby’s docs for regular expressions.

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