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Home/ Questions/Q 7165569
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T14:16:19+00:00 2026-05-28T14:16:19+00:00

I just started to learn C programming. In my book there is this piece

  • 0

I just started to learn C programming.
In my book there is this piece of code:

/*Code Start*/
/*This code is use to find the simple interest*/

main ()
{
int p, n;
float r, si;

p = 1000;
n = 3;
r = 8.5;

si= p*n*r/100;
printf("%f", si);

}

/*Code end*/

The output i got was ” 255.000000 “

I though i’ll modify it with scanf function so i wrote this:

/*Code Start*/

main ()
{
int p, n;
float r, si;

printf("Enter value for p: \n");
scanf("%d", &p);
printf("Enter value for n: \n\n");
scanf("%d", &n);
printf("Enter valuse for r: \n\n");
scanf("%d", &r);

si= p*n*r/100;

printf("\nYour Simple Interest is %f\n\n", si);
}

/*Code End*/

No matter what values i give to p,n,r the answer i get is always 0.000000..
I also tried giving the values, p=1000, n=3, r=8.5 but still i get 0.000000..

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  1. Editorial Team
    Editorial Team
    2026-05-28T14:16:19+00:00Added an answer on May 28, 2026 at 2:16 pm

    Firstly, your main problem: The %d specifier is only for integers, not floats or doubles. Use %f for floats.

    In addition, the main should return an int, this will do:

    int main() {
        /* your code */
        return 0;
    }
    

    Finally, I would recommend you make better use of white-space as it will vastly help with readability once you start making larger programs.

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