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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T17:53:07+00:00 2026-05-11T17:53:07+00:00

I just started using the MVCContrib grid in a test project. I’m having a

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I just started using the MVCContrib grid in a test project. I’m having a difficult time finding information on how to use it for edit/update/delete.

Can anyone point me to information on how to put a row into edit mode, or if there isn’t such a thing for that grid, discuss a best practice for editing list data in MVC.

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  1. Editorial Team
    Editorial Team
    2026-05-11T17:53:07+00:00Added an answer on May 11, 2026 at 5:53 pm

    It appears as if MVCContrib is a simple way to construct the HTML Table from a collection of model objects. It doesn’t appear as if has any ability to put a row into edit/update/delete “mode” similar to the WebForms GridView.

    However, it does look like you can handle that functionality however you want to. If you want to go to a separate page for edit mode, just put a link in one of the columns with that row’s id. The following is taken directly from: http://www.jeremyskinner.co.uk/2009/03/01/mvccontrib-grid-part-5-the-action-syntax/

    <% Html.Grid(Model).Columns(column => {
                column.For(x => x.Id).Named("Person ID");
                column.For(x => x.Name);
                column.For(x => x.Gender);
                column.For(x => x.DateOfBirth);
                    column.For("View Person").Named("").Action(p => { %>
                         <td style="font-weight:bold">
                        <%= Html.ActionLink("View Person", "Show", new { id = p.Id })%>
                     </td>
                    <% });
            }).RowStart((p,row)  => {     
                 if (row.IsAlternate) { %>
                       <tr style="background-color:#CCDDCC">
                 <%  }  else  { %>
                     <tr>
                 <% }
        }).Render(); %>
    

    Here it looks like they are wanting to direct the user to a View Person page: <%= Html.ActionLink("View Person", "Show", new { id = p.Id })%>.

    Good luck, and happy coding.

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