I just uncovered this confusion and would like a confirmation that it is what it is. Unless, of course, I am just missing something.
Say, I have these data declarations:
data VmInfo = VmInfo {name, index, id :: String} deriving (Show)
data HostInfo = HostInfo {name, index, id :: String} deriving (Show)
vm = VmInfo "vm1" "01" "74653"
host = HostInfo "host1" "02" "98732"
What I always thought and what seems to be so natural and logical is this:
vmName = vm.name
hostName = host.name
But this, obviously, does not work. I got this.
Questions
So my questions are.
-
When I create a data type with record syntax, do I have to make sure that all the fields have unique names? If yes – why?
-
Is there a clean way or something similar to a “scope resolution operator”, like
::or., etc., so that Haskell distinguishes which data type thename(or any other none unique fields) belongs to and returns the correct result? -
What is the correct way to deal with this if I have several declarations with the same field names?
As a side note.
In general, I need to return data types similar to the above example.
First I returned them as tuples (seemed to me the correct way at the time). But tuples are hard to work with as it is impossible to extract individual parts of a complex type as easy as with the lists using “!!”. So next thing I thought of the dictionaries/hashes.
When I tried using dictionaries I thought what is the point of having own data types then?
Playing/learning data types I encountered the fact that led me to the above question.
So it looks like it is easier for me to use dictionaries instead of own data types as I can use the same fields for different objects.
Can you please elaborate on this and tell me how it is done in real world?
Haskell record syntax is a bit of a hack, but the record name emerges as a function, and that function has to have a unique type. So you can share record-field names among constructors of a single datatype but not among distinct datatypes.
You can’t. You have to use distinct field names. If you want an overloaded name to select from a record, you can try using a type class. But basically, field names in Haskell don’t work the way they do in say, C or Pascal. Calling it “record syntax” might have been a mistake.
Actually, this can be quite easy using pattern matching. Example
As to how this is done in the “real world”, Haskell programmers tend to rely heavily on knowing what type each field is at compile time. If you want the type of a field to vary, a Haskell programmer introduces a type parameter to carry varying information. Example
Now you can have
VmInfo String,VmInfo Dictionary,VmInfo Node, or whatever you want.Summary: each field name must belong to a unique type, and experienced Haskell programmers work with the static type system instead of trying to work around it. And you definitely want to learn about pattern matching.