Question

I just wanna know how i can save the value and the index for my array “cadenaNumeros” in a integer, if the user entry is something like this : 123456789 or 48934013 or 183853025… etc.

I was thinking do it with a FOR, but my code didn´t work.

For example: if we have this array “123456789” the value will be 2 and index = 1 and this numbers save it in a integer.

I’m programming in ANSI C.

#include <stdio.h>
#include <stdlib.h>

void main()
{
    int a = 0, i = 0, indice, numero[20], vuelta, quedan, x;
    int cadenaNumeros[20000];
    int num, num2;

    printf("\n\nEscribe el numero de palancas: ");
    scanf("%d", &num2);

    printf("\n\nEscriba el numero de la palanca roja: ");
    scanf("%d", &num);

    printf("\n\nIntroduzca una cadena de numeros: ");
    scanf("%d", &cadenaNumeros);

    for(i = 0; cadenaNumeros[i] < num2; i++); {
        cadenaNumeros[0] == numero[x];
        printf("%d", numero[x]);
    }

    system("PAUSE");
    return 0;
}

Answer 1

int index = -1, i = 0;

// Assuming num2 is the number you're searching for
// And the array size is 20000
for( ; i < 20000; i++) {
    if( cadenaNumeros[i] == num2) {
        index = i;
        break;
    }
}

if( index != -1) {
    printf( "Found %d at index %d\n", num2, index);
} 
else {
    printf( "Number not found\n");
}